0=12x^2-260x+1050.

Solution for 0=12x^2-260x+1050. equation:

0=12x^2-260x+1050.

We move all terms to the left:

0-(12x^2-260x+1050.)=0

We add all the numbers together, and all the variables

-(12x^2-260x+1050.)=0

We get rid of parentheses

-12x^2+260x-1050.=0

We add all the numbers together, and all the variables

-12x^2+260x-1050=0

a = -12; b = 260; c = -1050;
Δ = b2-4ac
Δ = 2602-4·(-12)·(-1050)
Δ = 17200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{17200}=\sqrt{400*43}=\sqrt{400}*\sqrt{43}=20\sqrt{43}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(260)-20\sqrt{43}}{2*-12}=\frac{-260-20\sqrt{43}}{-24}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(260)+20\sqrt{43}}{2*-12}=\frac{-260+20\sqrt{43}}{-24}
$